Solow Residual: A Macroeconomic Approach to Technological Progress

We finally stop pinning labor productivity A at 1, bundle it with N into 'effective labor' AN, and roll into the Solow residual framework for thinking about tech progress.

So far, the indicator of economic growth we’ve been using is per-capita GDP — Y/N!!!

We said the variables that determine this are K, N, and F(~), and we already chewed on K for a while.

This time, let’s turn our attention to the ’level of technology’ that’s hiding inside F(~).

Just a tiiiny bit more detail than the F(~) we covered before, so don’t get your hopes up too high.

The reason: we’re going to take labor productivity A — which we’d been pinning at 1 the whole time — and let it actually be a variable.

Wait!! Why is A making a comeback here?!

Can we just say labor productivity A represents the level of technology?!

Eh, sure, close enough… (technically they’re different things, but whatever.)

Let’s just go ahead and call A the ‘state of technology.’

We had Y = AN, right??? Plus,

we’d also assumed another variable K that helps determine Y. So the function F that gives Y becomes

Y equals F of K and AN

— let’s view it like this.

The variables we’re feeding in are K and AN.

The thing I want to emphasize is NOT that A and N are being treated as two separate inputs.

It’s that we’re lumping AN together and treating it as a single variable.

Why does that matter? Saying “the level of technology doubled” means 2AN…

but that’s only the story if the amount of labor N is held constant.

Like, if technology actually advances, are they really gonna leave the headcount alone? Really? Wouldn’t they trim a few people? Come on.

So if you try to think of A and N separately, your head starts to hurt.

That’s why the move is to lump AN together, call it “effective labor,” and keep going from there.

Let’s keep that view and push on.

Y equals F of K and AN

I want to draw this on a coordinate axis.

Now that we’re treating AN as ’effective labor,’ we can apply the exact same logic from Chapter 10 — verbatim.

What was that logic? I’m just going to swap ’labor’ for ’effective labor’ everywhere.

When K = 5 (machines), AN (effective labor) = 5 people,

let’s say Y = 5.

Drawing of 5 machines and 5 workers

But say we bump it up by another 5 machines and another 5 effective labor!!!!

What does output Y become?!?!?!?!?!

Drawing of 10 machines and 10 workers

Yeah!!! It would double, since we’re producing 5 more of the exact same thing?!?!?!?

Which means our function F has the following property.

This kind of property:

X times Y equals F of xK and xAN

We’re going to milk this property.

Let’s plug in x = 1/AN!!!

Y over AN equals F of K over AN and 1

That’s what we get.

And to clean up the notation, let

F of K over AN and 1 is written as small f of K over AN

— shorthand it like that.

Then the graph comes out exactly the same shape, right?!?!?! (The shape, anyway. Just the shape.)

OK and now we’ll also need to peek back at the chain of logic we already walked through.

Because the same exact thing applies here.

Under the assumption NX = 0 and T − G = 0, we get I = S.

Savings S is proportional to income Y, and if we call that proportionality constant s, then S = sY,

so I = sY. Tack on a time index and

I sub t equals s times Y sub t

we get this.

Now capital K at time t, K sub t, minus what depreciation eats away, flows forward into K sub t plus 1, so capital (flow + stock) at time t+1 becomes

K sub t plus 1 equals 1 minus delta times K sub t plus I sub t, which equals 1 minus delta times K sub t plus s times Y sub t

K sub t plus 1 over AN minus K sub t over AN equals s Y sub t over AN minus delta K sub t over AN, and the same line written with s times f of K sub t over AN

Wow~~~~ we got here through the exact~~~same chain of logic.

OK so in this chapter, we said we’d release the assumption that N is constant.

Why release it? Because we’ve introduced time as a variable, and we need to look at how things evolve as time passes.

We said we’d let A vary because it changes over time —

but it’s also kinda unreasonable to keep N nailed down as a constant,

so while we’re at it, we’re dropping that assumption for N too!~

If A and N both change like that, which part of the equations above do we need to fix? It’s

K sub t plus 1 over AN minus K sub t over AN equals s times f of K sub t over AN minus delta K sub t over AN, with the last term in red

— that part there in the spotlight.

Capital per unit of effective labor

gets eaten away by the depreciation rate δ, AND on top of that, g sub A — the rate of technological progress, and g sub N — the rate of population growth. It’ll get knocked down by the sum of those rates.

(Quick example — if depreciation is 10%, the rate of technological progress is 2%, the rate of growth in workers is 1%, then from year t’s capital stock, delta plus g sub A plus g sub N, times K sub t gets shaved off, and what’s left flows in as year t+1’s capital stock!!!)

That is,

K sub t plus 1 over AN minus K sub t over AN equals s times f of K sub t over AN minus the sum delta plus g sub A plus g sub N, times K sub t over AN

— this is the bill we pay for letting those variables roam free!!!!!!!

Let’s call that newly minted total decrease rate Δ!!!

K sub t plus 1 over AN minus K sub t over AN equals s times f of K sub t over AN minus capital Delta times K sub t over AN

Why bother packing it like this????????????????

So we can run the exact~~~same chain of logic we ran before!! heh heh heh heh heh

Go check the earlier post!!! Linking it ( The Relationship Between Savings Rate and Output (Macroeconomics I Studied #11) )

The fact that the conclusion comes out the same means

Y star over AN

a steady state exists!

And the value of Y(*) doesn’t depend on the initial capital stock per unit of effective labor!!!

But — there’s a twist this time.

The steady state here is

The pair Y star over AN and K star over AN

these guys are constant.

But meanwhile, AN itself is changing as time passes.

How is it changing? It’s growing at rate g sub A plus g sub N — this rate.

So back when N was held constant, Y had a hard ceiling, and the rate of change of Y star over AN in the steady state was 0. Here, though, Y and K are both g sub A plus g sub N — changing together at this rate.

Summary:

The rate of economic growth in the steady state is

G sub A plus g sub N

this.

If g sub A plus g sub N is zero, the rate of economic growth is zero.

In this case, this kind of growth rate is called the “balanced growth rate” — g sub A plus g sub N — that’s it.

OK, before we move on, let’s clear up one nagging question.

g sub N — the growth rate (or rate of change) of labor — that one doesn’t seem too crazy to pin down with stats from the bureau of statistics or wherever.

But seriously, what on earth is g sub A — the rate of technological progress — and how the heck do you put a number on it!!!!

Let me introduce something for that.

There are various ways to quantify it, and among the ones still in active use today,

I’ll introduce Robert Solow’s method from ‘57.

Change in output Y equals the real wage times the change in labor

we have this, right?!?!?!

Delta Y equals W over P times Delta N

To express it as a rate of change,

Delta Y over Y equals W N over P Y times Delta N over N

we can shuffle things like this,

and write

Output growth due to labor equals W N over P Y times g sub N

W N over P Y

where α is “the share that wages take of total output.”

So if we call labor’s share α and rewrite,

Output growth due to labor equals alpha times g sub N

is the change in output attributable to changes in labor. (Naturally α is a number between 0 and 1.)

Then there’s gotta be a chunk attributable to capital too, right?

Output growth due to capital equals 1 minus alpha times g sub K

We take these two measurable things and subtract them

from the actually measured

Total output growth g sub Y

And whaddya know — there’s a leftover!!!!!

So

Total output growth equals growth due to labor plus growth due to capital plus the residual

— this is called the Solow Residual.

Why does the residual show up? Probably because of technological progress.

Going with that thought,

it seems fair to label that residual

Output growth due to technological progress, g sub Y

— yeah, that works!!!!!

BUT!!!!! No matter how juicy the tech is, if there’s no labor around, technological progress is completely useless.

Labor share times g sub A equals output growth due to technological progress

is how it’s defined, apparently^^

Not too gnarly a concept.

Comments

Discussion happens via GitHub Discussions. You'll need a GitHub account to comment.