Relativistic Correction and the Fine Structure of Hydrogen

We're back to hydrogen again?! Using perturbation theory, we dig into fine structure — relativistic corrections, spin-orbit coupling, and the Lamb shift.

Now that perturbation theory is available, it is time to return to the hydrogen atom. The familiar nonrelativistic model is extraordinarily successful, but it is not exact. Several small effects shift its energy levels:

  1. the relativistic correction to the electron’s kinetic energy;
  2. spin–orbit coupling between the electron’s orbital and spin angular momenta;
  3. the Lamb shift, produced by the interaction of the electron with the quantized electromagnetic field; and
  4. hyperfine structure, associated with the magnetic interaction between the electron and the nucleus.

The first two contributions are usually discussed together under the heading fine structure. Their scale is tiny—roughly of relative order $10^{-4}$ in hydrogen—but measuring and explaining such small discrepancies is part of how physical theory becomes more precise. The Lamb shift is smaller still and requires quantum electrodynamics, while hyperfine structure belongs to another layer of the spectrum.

This post concentrates on the first item: the leading relativistic correction to the kinetic energy. Spin–orbit coupling comes next.

1. Why the nonrelativistic kinetic energy needs a correction

In the Bohr picture, the characteristic speed of the ground-state electron is of order $\alpha c$, approximately $c/137$. That is slow enough for a nonrelativistic treatment to work well, but fast enough for the first relativistic term to leave a measurable trace.

The Schrödinger Hamiltonian uses the classical expression

Nonrelativistic kinetic energy one half m v squared

or, in momentum form, $T=p^2/(2m_0)$. Relativistically, however, momentum is

Relativistic momentum p equals m zero v divided by the square root of one minus v squared over c squared

as reviewed in Modern Physics #5: Relativistic Mass, Momentum, and Energy. The exact kinetic energy is the total energy minus the rest energy:

Relativistic kinetic energy written as square root of p squared c squared plus m zero squared c fourth minus m zero c squared

Thus

$$ T_{\mathrm{rel}}=\sqrt{p^2c^2+m_0^2c^4}-m_0c^2 =m_0c^2\left[\sqrt{1+\frac{p^2}{m_0^2c^2}}-1\right]. $$

The low-momentum expansion

For $p/(m_0c)\ll1$, expand the square root in a Taylor series:

Taylor expansion of relativistic kinetic energy through the negative p fourth correction

Equivalently,

$$ T_{\mathrm{rel}} =\frac{p^2}{2m_0}-\frac{p^4}{8m_0^3c^2}+O\!\left(\frac{p^6}{m_0^5c^4}\right). $$

The first term is the ordinary nonrelativistic kinetic energy. The next term is therefore the leading perturbation:

$$ H'_{\mathrm{rel}}=-\frac{p^4}{8m_0^3c^2}. $$

Leading relativistic perturbation Hamiltonian and its first-order expectation value in a hydrogen eigenstate

For an unperturbed hydrogen eigenstate $|n,\ell,m\rangle$, first-order perturbation theory gives

$$ E_{\mathrm r}^{(1)} =\left\langle n,\ell,m\middle|H'_{\mathrm{rel}}\middle|n,\ell,m\right\rangle =-\frac{1}{8m_0^3c^2}\left\langle p^4\right\rangle. $$

2. Rewriting the momentum operator with the Schrödinger equation

The fourth power of momentum looks awkward, but the time-independent Schrödinger equation supplies the useful identity

Time-independent Schrödinger equation rearranged to give p squared psi equals two m times E minus V times psi

that is,

$$ p^2|n,\ell,m\rangle=2m_0(E_n-V)|n,\ell,m\rangle. $$

Using the Hermiticity of $p^2$ on the hydrogen bound-state domain, we can apply this relation to both sides of the expectation value:

Derivation converting the expectation of p fourth into expectation values of E minus V squared

Therefore

$$ E_{\mathrm r}^{(1)} =-\frac{1}{2m_0c^2}\left\langle(E_n-V)^2\right\rangle =-\frac{1}{2m_0c^2} \left[E_n^2-2E_n\langle V\rangle+\langle V^2\rangle\right]. $$

Because $E_n$ is a number—not an operator—it passes straight through the expectation value.

Coulomb expectation values

For hydrogen,

$$ V(r)=-\frac{e^2}{4\pi\varepsilon_0r}. $$

The remaining ingredients are consequently $\langle r^{-1}\rangle$ and $\langle r^{-2}\rangle$:

Hydrogen Coulomb potential followed by the required expectation values of one over r and one over r squared

The previous post on Kramers’ relation established

Hydrogen expectation values one over r equals one over n squared a and one over r squared equals one over ell plus one half times n cubed a squared

or

$$ \left\langle\frac1r\right\rangle=\frac{1}{n^2a}, \qquad \left\langle\frac1{r^2}\right\rangle =\frac{1}{(\ell+\tfrac12)n^3a^2}, $$

where $a$ is the Bohr radius.

3. The first-order relativistic energy shift

Insert the Coulomb potential and the two expectation values into the perturbative expression:

Substitution of the Coulomb expectation values leading to the closed relativistic energy correction

After simplifying with the hydrogen energy $E_n$, the result is

$$ \boxed{ E_{\mathrm r}^{(1)} =-\frac{E_n^2}{2m_0c^2} \left(\frac{4n}{\ell+\tfrac12}-3\right) }. $$

The numerator that appears here is

Hydrogen energy E n squared

so the relative scale of the correction is set by $|E_n|/(m_0c^2)$, of order $\alpha^2$ for low-lying hydrogen states. This explains why the correction is often summarized as being around one part in ten thousand, although its exact size depends on $n$ and $\ell$.

Most importantly, the unperturbed Coulomb energy depends only on $n$, whereas this correction also depends on $\ell$. The relevant first-order shift is

First-order relativistic energy correction E r superscript one

and its $\ell$ dependence begins to lift the accidental degeneracy of the nonrelativistic hydrogen spectrum. This is one of the ingredients of fine structure; combining it consistently with spin-dependent and contact terms requires the next stage of the analysis.

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