Fundamental Understanding of Special Relativity

A fun, casual breakdown of special relativity — from inertial frames and Maxwell's equations to why light always clocks in at c no matter where you are lololol.

The master of electromagnetism, Maxwell, says in his Maxwell’s equations that “in any inertial frame, as long as it’s an inertial frame, the speed of light in a vacuum is c.”

So, when you do a physics experiment, a place where you get the same results as in your physics textbook — that kind of place is called an inertial frame. To put it a bit more rigorously, “a frame in which Newton’s laws of motion hold” is called an inertial frame!!!

A representative example of a place that is NOT an inertial frame: the inside of a car flooring the accelerator like crazy. In a place that isn’t accelerating, objects that were sitting still aren’t supposed to move, but inside a car flooring the accelerator like crazy, things that were sitting still suddenly fall, and the stuff you were eating spills, right??? Anyway.

So, as a representative example of places that are different but the exact same kind of inertial frame: there’s my room where I’m just sitting st~~ill, and there’s also a place that is the exact!!!~~ same kind of inertial frame as that — “a place moving at constant velocity.”

Why is a place moving at constant velocity the same as a stationary room, you ask?

You’ve all ridden in a car or train moving at a constant~ speed, so you know that feeling, right? So now, in your head, imagine that train or plane or car moving at constant velocity. And in that imagination, using black spray paint or contact paper or something, the windows, floor, ceiling ~~ just imagine you’re covering everything up so you can’t see the outside situation at all. Did you cover it all up in your head?

Now in that mental image, with everything painted black, sit right in the middle…. And I’m going to ask you a question.

“What could you look at to be sure whether the place you’re in right now is moving at constant velocity, or just sitting still?”

Hahahahaha… physics is kind of like this, isn’t it? lol Anyway, lol.

In a situation like that, there is nothing whatsoever by which you could tell them apart…. hehe

So now, the real special relativity begins~ In Maxwell’s equations, they say that in any inertial frame the speed of light in a vacuum is always c ≈ 300000 km/s. But this is where it starts getting a little weird.

Sketch: a person in a spaceship moving at constant velocity and a person on the ground each fire a laser and each sees light at speed c

Okay, okay, okay: inside a spaceship moving at constant velocity, or us just standing here on the ground — if we fire a laser and look at that light, both people will see it exactly the same way. Right?! You’re sure of that?! And Maxwell’s equations still don’t have any contradiction yet, because we said that in any inertial frame, light would appear equally as c! But then!!!

Sketch: person 1 on the ground looks at the light from the laser of person 2 in the spaceship

Mental breakdown. When person 1 looks at person 2’s laser, it must also appear as c!!! Because the place person 1 is in is an inertial frame, and the light coming from person 2’s laser is still, somehow or other, light! So that light must also appear at the speed of light c!!!

But isn’t that weird?! If you throw a ball forward at 10 km/s from a train moving at 50 km/s, it’s common sense for us that the person outside sees that ball as moving at 60 km/s! But we’re saying that light doesn’t work that way!

A ball doesn’t, but light does?? How can that be?

Lol, that makes no sense. OMG.

In that case, does that mean Maxwell’s equations are wrong?! Is the theoretical framework incomplete?

(To spoil things a little, if Maxwell’s equations were wrong, then “in any inertial frame the speed of light is c” would be a wrong statement, and if not that, but rather Newtonian mechanics is wrong, then “velocity addition (Galilean transformation)” would be wrong ~ )

So it comes down to this: one of the two — Maxwell’s electromagnetism or Newton’s mechanics — is wrong.

Michelson, Morley and the ether

The people who experimented on this were none other than Albert Michelson & Edward Morley (1887). Actually, these gents weren’t exactly running an experiment to uncover that contradiction; the experiment these gents did was actually an experiment to uncover a hypothetical substance called “ether.” But, to cut to the conclusion, they did not find the ether wind they expected. (That alone didn’t rule out every possible ether theory, but it was a heavy blow to the idea.)

Ah…. should I explain ether a bit too? I’ll just do it briefly. A wave is energy being transmitted, and for the waves people knew back then, that energy needs a “medium” to travel through. For surface waves the medium is water, for the sound waves we call sound, the medium is air particles, and heat (thermal energy flowing from hot to cold; temperature tells you how hot, it isn’t the energy itself) conducted through the air is passed along by the air molecules themselves. But, according to Maxwell’s equations, light also travels in the form of a wave, and we called that an electromagnetic wave, right?? So they were asking, what on earth is the medium that allows this light to propagate?

People reasoned that, first, since it’s a wave, there has to be a medium, but we don’t know it yet, so they gave that yet-unknown medium the name “ether.” And Michelson and Morley did their experiment to find that ether.

Sketch of the Earth orbiting the Sun

The Earth is orbiting around the sun like this,

Sketch of the Earth at position 1 and position 2 on its orbit around the Sun

and if we think, like the people of old, that there’s a hypothetical substance called “ether,” these gents believed that the hypothetical substance ether formed a “rest frame,” and that light was mediated through it. Then the Earth’s motion relative to the ether would be different from moment to moment, and what this means is that when the Earth is at position 1 relative to the sun versus when it’s at position 2, the effect of the ether acts in the opposite direction.

So did Michelson and Morley literally clock the speed of light at position 1 and at position 2? Not quite. They used an interferometer: one beam split into two arms at right angles, each half running out and back, then recombined. If an ether wind were blowing past the Earth, the two arms would take slightly different times, and turning the apparatus around would make the interference fringes slide by a predictable amount. They floated the whole thing on mercury and rotated it slowly… The result was….. almost no shift, far less than the ether theory predicted: the famous null result. In every direction, light behaved as if its speed were the same. (The orbit sketch is the intuition for why some ether wind should show up somewhere along the orbit.) Please pay attention to “the speed of light came out the same in every direction.”

The reason I brought this up is — Einstein never directly said so in his autobiography or any speech or anything, but many scientists, asking why Einstein, all on his own, suddenly made an assumption that seemed totally absurd at the time — “the speed of light is always constant at c, whether for a person in motion or a person at rest” — speculate that the reason for that…… well, perhaps? probably? is that the 1887 experiment maybe had a little bit of an influence on him~~, apparently.

That is, Einstein’s assumption probably didn’t just pop out for no reason whatsoever, right? There was probably some historical background behind it — hearing that, I found it kind of interesting.

Einstein’s assumption, and simultaneity

Anyway! At least for now, Maxwell’s equations aren’t wrong.

So then how on earth is that contradiction resolved?!

That’s exactly the SR (special relativity) Einstein published in 1905~, and for now, slamming down the assumption that the speed of light is the same c in every inertial frame, and adopting for the transformation between inertial frames not the Galilean transformation but “a different transformation” — let’s keep going with that.

Even if you don’t know what that means right now, you’ll clearly understand it later hehe

With this, the concept of simultaneity — Newton’s “absolute time” — gets broken,,,, because according to Newtonian theory, events that happen simultaneously in one inertial frame have to be simultaneous in another inertial frame too. The reason being, time flows the same in every inertial frame — it’s “abs!olute! time!”!!

What this means is,

Sketch: inside a spaceship, light from the left and light from the right are emitted at the same time and reach the person in the middle at the same time

if, in Newtonian theory… the kind of event above — and here, such an event means, as in the picture, ‘inside a spaceship moving at constant velocity, light 1 coming from the left and light 2 coming from the right set off simultaneously and reached the person in the middle simultaneously… that kind of thing’ — if a stationary person outside the spaceship looks at this event, the content of Newtonian theory is that it should also appear simultaneous to the person outside.

But!!! With Einstein’s assumption “the speed of light is always c”, both beams move at c for the person outside too, and the meeting in the middle is a single event that everyone agrees on: the two beams arrive together for everybody. What the person outside disagrees about is the sending. In their frame the person in the middle is moving forward, toward the front beam and away from the back one, so the beam from the back must have set off earlier. “Emissions that are simultaneous inside the ship are not simultaneous outside.”

This is what we mean by simultaneity being broken.

Time dilation

And now, at last, bit by bit, the word “time” makes its appearance. So now let’s describe it properly, putting in the time interval!! hehehe Now I’m going to play with this picture a bit more numerically.

The same sketch again: person 1 on the ground and person 2 in the spaceship

In this picture, say the person in the spaceship doesn’t shoot the laser forward, but shoots it so that the light bounces up and down. (Careful, the numbers swap here: from now on, person 1 is the one inside the spaceship and person 2 is the one on the ground.) Then the light person 1 sees will be the black dotted line in the picture below, and the light person 2 sees will be the red dotted line in the picture below.

Sketch: light bouncing up and down in the spaceship, a vertical dotted line for the person inside and a slanted red dotted line for the person outside

Like this???? Now let me fill in some numbers.

The same sketch with numbers: height L, horizontal distance vt over 2, and the slanted path of length the square root of the square of vt over 2 plus L squared

Ta-da-da-dan~~~~~~~ Even without any special explanation, just by filling things in like this, you all get it, right?

Sketch: the bouncing light as seen from inside the spaceship by person 1 and from the ground by person 2

OK, so, if Einstein’s assumption is correct, the person observing from inside the spaceship saw the black dotted line as light, and since that was speed c, let’s say the time for light at speed c to travel a distance of 2L is t. No wait, no — rather than putting it that way, let’s take: the speed of the light that travels a distance 2L over time t is c.

And the person observing from the outside inertial frame also saw it at speed c, and they say they observed it over time t’. Over the time t prime, the light travels 2 times the square root of L squared plus the square of vt over 2, and they still see its speed as c.

So if Einstein is right, the former is c equals 2L over t and the latter is

Formula: c equals 2 times the square root of L squared plus the square of vt over 2, all over t prime

so

Formula: 2L over t equals 2 times the square root of L squared plus the square of vt over 2, all over t prime

that’s what this says, and according to the picture above,

Inequality: 2L is less than 2 times the square root of L squared plus the square of vt over 2

this inequality is really, super obviously obvious.

Then, how strangely, t is less than t prime — that’s what it’s saying?!

Yes, that’s right.

Sketch: the same picture with a smiley at the start and a smiley at the end of the light path, joined by a green arrow

Clearly for person 1 inside the spaceship the time it took to go from smile to smile was t, and for person 2 outside, they were clearly watching for t’!!!

And if we satisfy Einstein’s slammed-down assumption, “the speed of light is always c,” we got the conclusion t < t'!

Aaagh! Yes, so now we can say it like this. Event: the event of the spaceship going from smile to smile. If the time you see that event in, riding on the spaceship, and the time you see that event in, sitting on the ground, are different, then those contradictions stop being contradictions → time dilation

And what about distances? The two smiles mark where the same clock is at two ticks. For person 1, riding with the clock, it hasn’t moved at all between the ticks: the distance is 0. For person 2 on the ground, the clock has moved $vt'$ in the meantime. That’s how far one clock travels, not a length of the ship. Lengths are a separate story: to measure the spaceship’s length (along its direction of motion) you mark both ends at the same time in your own frame, and then person 2 gets a shorter length than person 1, $L = L_0\sqrt{1 - v^2/c^2}$. → Length contraction

For practice problems related to time dilation and length contraction, I’ll just punt to “Modern physics as I studied it.”

Time Dilation in Special Relativity (Modern Physics I Studied #1)

Length Contraction in Special Relativity (Modern Physics I Studied #3)

The Twin Paradox in Special Relativity (Modern Physics I Studied #4)

Relativistic Mass, Momentum, and Energy (Modern Physics I Studied #5)

Actually, let me confess here — what I was mainly going to cover in this special relativity series was actually…………. “a non-Euclidean geometric approach”…hehehehehe

So I’ll leave the basics here, and in the next post I’ll try the non-Euclidean geometric approach! See you next time lol


Heads-up. The figures here are the original notes, slips and all. A few things to watch for:

  • In the light-clock pictures the ship’s sideways distance during half a round trip is $vt'/2$: it is the outside observer who sees the ship move, during the outside time $t'$. The pictures write $vt/2$. With $vt'/2$ the equations give $t' = t/\sqrt{1 - v^2/c^2}$; the inequality $t < t'$ holds either way.

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