Phase Coexistence Curves of Water

We draw out phase coexistence curves using the Clausius-Clapeyron equation and figure out why water's solid-liquid line has a negative slope — spoiler: hydrogen bonding!!

Alright alright alright, anyways, so the takeaway from what we’ve been discussing up to now is “the equation for the phase coexistence line = the Clausius-Clapeyron equation”. And yeah.

Now let’s draw it!!!! hehehehe

Integrating the Clausius-Clapeyron equation: dp/dT = L/(TΔV), so dp = (L/(TΔV)) dT and p = (L/ΔV) ln T + Constant

Let’s just draw it roughly like a log function (that’s what you get if $L$ and $\Delta V$ stay constant). Then it would look like this.

Rough sketch of p against T: a log-shaped curve that rises from the T axis and flattens out, dashed below the axis

Something like this, right?

(Strictly speaking, only the solid-liquid line keeps $\Delta V$ roughly constant. For vapour $\Delta V \approx RT/p$, and the Clausius-Clapeyron equation really gives last post’s $p = e^{-L/RT + C}$, which gets steeper as $T$ rises instead of flattening out. For comparing the two lines, though, this rough sketch does the job.)

Okay, so let’s think of this picture as the phase coexistence line between vapour and liquid that comes from the Clausius-Clapeyron equation, and let’s derive the phase coexistence line between solid and liquid. The equation here will be the same as above too, but this part will be different.

The same result, p = (L/ΔV) ln T + Constant, with the ΔV in red

Forget about L, let’s look at V. This delta value will differ depending on the substance, but ΔV has something in common.

V_vapour − V_liquid will be way bigger than V_liquid − V_solid

This point right here….hehehe So then the log function between liquid and solid will be steeper than the log function between vapour and liquid. Then I guess we can just overlay it like this and draw it.

The sketch again with a steeper red curve for the solid-liquid line, crossing the black vapour-liquid curve

Ah, that crossing suggests where to look for a triple point! To establish it, all three phases must have the same chemical potential; these rough curves alone are not a proof.

(it’s a pretty qualitative analysis though;;; hehehe)

This post was actually all for the sake of what comes below.

Actually, for the case of water you also learn this in middle/high school, but the phase coexistence line looks like this hehehe

Water’s phase diagram as sketched: the red solid-liquid line leans back onto the black curve, with solid on the left, liquid at the top and vapour below

It’s like this. The point is that the gradient of the phase coexistence line between solid and liquid is (-). What it being negative means is

The Clausius-Clapeyron equation: dp/dT = L/(TΔV)

Negative slope: V_liquid − V_solid is less than 0, so V_liquid is smaller than V_solid

that’s what it means. That’s really weird, isn’t it?

If we represent solid, liquid, gas simply,

Dots for gas, liquid and solid: the particles get closer at each step, and the solid is a tight lattice

this seems reasonable, right?!?! But in the case of H₂O it ends up saying

The same for water: water vapour, water and ice, where the ice dots are spread out more than the water dots

So why does H₂O have this kind of property?????

We learned this in high school chemistry, right?!?! It’s hydrogen bonding!!! FON-H-FON-H ~~~~~~ that’s how I memorized it lolol

The hydrogen-bond mnemonic FON - H - FON, next to F—H—F with O and N listed under each F

Let me try interpreting “low temperature” as “low contained energy” (what counts as contained energy: translational kinetic energy, rotation, vibration, etc.)

Water vapour: three water molecules (red O, blue H) zooming off in different directions

Water molecules at high temperature, i.e. water vapour, have so much contained energy that, as in the picture above, you could say they’re thrashing around like hell. Then at low temperatures:

Cold water molecules huddled together any old way

Since the contained energy is low, they don’t move, don’t rotate, don’t vibrate, right?????

Not quite! In ice they stay near lattice sites instead of roaming freely, but they still vibrate. Cooling reduces thermal motion; it does not make the molecules completely motionless. These guys settle into an ordered, open structure.

Because the difference in electronegativity between H and O is super big — ummm~~~~ the electronegativity of O is so big that it pulls in the (-) influence of H — water molecules end up with polarity. So it’s not that they’re huddled together haphazardly like above: they line up in rows and columns.

Water molecules lined up in an open ring, linked by hydrogen bonds

They end up lined up in rows and columns like this, and if the temperature gets juuuust a little bit higher than this,

One water molecule with red arrows at its O-H bonds and a red X: heat does not split the molecule

rather than the thermal energy dissociating the water molecules like this,

The ring again with red arrows cutting the hydrogen bonds and a green tick: heat breaks the hydrogen bonds

the thermal energy is used to break the hydrogen bonds like this.

So compared to when it was ice, the liquid ends up juuust a little~ more packed together hehehehe

This isn’t chemistry class, so I won’t get into stuff like how liquid H₂O near atmospheric pressure has its maximum density around 4℃, and so on.

Just get that this hydrogen bonding makes water behave differently from ordinary particles: icebergs float on water, the Han River freezes from the surface down, stuff like that…heh.hehehehe

Pleeease look forward to the next post hehehe It’s gonna be really fun heh

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